Question

Guys, need assistance pls...

Answer 1

\[\frac{ \sqrt{15} }{ 5\sqrt{20} }\]

Answer 2

@EngrChong

Answer 3

help plsss.

Answer 4

Are you trying to factor it out?

Answer 5

division

Answer 6

@Adjax

Answer 7

Just give me a sec. I'm trying to see what I can do:)

Answer 8

\[\frac{ \sqrt{15} }{ 5\sqrt{20} }=\frac{ \sqrt{15} }{ \sqrt{5\times 5 \times 20}} = \frac{ \sqrt{15} }{ \sqrt{500}} = \frac{ \sqrt{15} }{ \sqrt{2 \times 2 \times 5 \times 5 \times 5} } = \frac{ \sqrt{15} }{ 10\sqrt{5} }\]

Answer 9

\[\frac{ \sqrt{3} }{ 10 }\]

Answer 10

ryt?

Answer 11

No

Answer 12

yes he is

\[=\frac{ \sqrt{3} }{ 10 } \approx 0.17320508075688772935274463\]

Answer 13

why not? your dividing them ryt?

Answer 14

Oh my bad didn't do my math right

Answer 15

Its actually division of radicals..

Answer 16

then how about this....

Answer 17

\[\frac{ \sqrt{3x^2y^3} }{ 4\sqrt{5xy^3} }\]

Answer 18

very easy:

\[\frac{ \sqrt{3x^2 \times y ^3} }{ 4\sqrt{5xy^3} } = \frac{ xy \sqrt{3y} }{ 4y \sqrt{5xy} }\]

Answer 19

thats final?

Answer 20

so what's you answer?

Answer 21

\[\frac{ x \sqrt{3} }{ 4\sqrt{5x} }\]

Answer 22

you can simplify more:
\[=\frac{ x \sqrt{3y} }{4 \sqrt{5xy} }\]
y cancels out

Answer 23

how about x?

Answer 24

you cam do more cancelling if you want...I just liked to see the the non-canceled view..the equation seems to be beautiful

Reason it out yourself how can you cancel x when there's nothing common

Answer 25

I hope you got the reasoning

Answer 26

\[\frac{ \sqrt{15x} }{ 20 }\]

Answer 27

what?...

Answer 28

how you arrived at this result this is not possible bro

Answer 29

there?