Question

please help me in algebra 1!!

Task 2

Part 1. Create two radical equations: one that has an extraneous solution, and one that does not have an extraneous solution. Use the equation below as a model.

a√x+b+c=d

Use a constant in place of each variable a, b, c, and d. You can use positive and negative constants in your equation.

Part 2. Show your work in solving the equation. Include the work to check your solution and show that your solution is extraneous.

Part 3. Explain why the first equation has an extraneous solution and the second does not.

Answer 1

any particular question ?

Answer 2

i dont even know what it wants me to do

Answer 3

please i at least need solution to part one!

Answer 4

\[a\sqrt{x+b}+c=d\] right?

Answer 5

yes

Answer 6

and you want it to have a solution? lets work backwards

Answer 7

well i need to make an equation that is extraneous and not extraneous

Answer 8

lets put
\[2\sqrt{x+1}+2=6\] and solve \[2\sqrt{x+1}+2=6\\
2\sqrt{x+1}=4\\
\sqrt{x+1}=2\\x+1=4\\
x=3\]
in this case \(3\) is not an extraneous solution because it works

Answer 9

ok so how do you make it extraneous?

Answer 10

you could make the number on the right negative
that would work
try
\[2\sqrt{x+1}+2=-1\]

Answer 11

or to make it easier try
\[2\sqrt{x+1}+2=-4\]

Answer 12

whatis extraneous though?

Answer 13

solve and see that it is "extraneous" in that the solution does not work

Answer 14

\[2\sqrt{x+1}+2=-4\\
2\sqrt{x+1}=-6\\
\sqrt{x+1}=-3\\
x+1=9\\
x=8\] but \(8\) is not a solution to the original equation

Answer 15

so its not extraneous?