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Mathematics 15 Online
OpenStudy (anonymous):

WILL RECIEVE FAN AND BEST RESPONSE!!!!!!!! (question in thread)

OpenStudy (anonymous):

Shane drew 3 squares with each side equal to n units. For each square, he does something different to it according to each part below. Part A: Shane increased the length and width of the square by m units each. What will be the change in the area of the original square? Show your work. (4 points) Part B: Shane decreased the length and width of the square by m units each. What will be the change in the area of the square? Show your work. (3 points) Part C: Shane increased the length of the square by m units and decreased its width by m units. What will be the change in the area of the square? Show your work.

OpenStudy (anonymous):

I did part a and b I need help with c

OpenStudy (anonymous):

wait never mind i need help with the question all of it

OpenStudy (anonymous):

@camerondoherty @uri

OpenStudy (anonymous):

@SolomonZelman @satellite73

OpenStudy (anonymous):

@ur

OpenStudy (anonymous):

@ParthKohli

OpenStudy (anonymous):

@KayLeeBaBii plz help

OpenStudy (anonymous):

i only need help with part c

OpenStudy (anonymous):

~well ok, since he increases the length and width of each square by 'm', then the measure of each will be n+m ~ so yahh the area will increase, because the formula for area is length x width, and if both the length and with increase then the area will definitly increase too ~ make sense??~

OpenStudy (anonymous):

yes but how would i make an equation and show the change in the area

OpenStudy (anonymous):

Im not really surr but this is what i would put part a: increases in area because u are adding the same value twice, part b: decrease in area because you are subtracting the same value twice part c: area remains the same, because after u add that value u subtract it again...so its stays the same

OpenStudy (anonymous):

Thank You thats the best anyone could do instead of ignoring me. u just received a fan and best response

OpenStudy (anonymous):

Lol thanks !

OpenStudy (anonymous):

lol

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