Given f(x)=x^2-8 and g(x)= (x+1)/x, find (g°f) (1)
to find (fog) multiply what the f(x) AND g(x) together.
(x²-8) × [ (x+1)/x ]
(x²-8)(x+1) --------- x x³ + x² - 8x - 8 -------------- x
to finis the problem, plug in 1 for x. x³ + x² - 8x - 8 (into -------------- ) x
(I can use latex this or next time if you want) Let me know if you \(\Large\color{ blue }{\Large {\bbox[5pt, white ,border:2px solid white ]{ need~~~help? \rm{\Huge✍} }}}\)
I got eight
Is it ftimes g or fog?
I believe it's fog. because it had that degree symbol not *
Solomon do I plug in 1 for all x's??
@SolomonZelman
these are my answers choices a. 8/7 b. 8 c. 6/7 d. -8 and by solving I got 8. Am I correct?
by plugging in 1, i et 1 + 1 - 8 - 8 ---------- 1 = -14/1 But that is not an Upton -:(
I did (f×g)... oops
ooo no wonder why i was confused.
f(x)=x²-8 g(x)= (x+1)/x, find (g°f) (1) (g° f)(x)= ( [x²-8] +1)/ [ x²-8] (g° f)(1)= ( [1²-8] +1)/ [ 1²-8] (g° f)(1)= ( -7 +1)/ -7 (g° f)(1)=-6 / -7 = 6/7 Option C
Sorry for my mistake.
It's fine(: Thanks you so much for the help!
Anytime ! (I was offline, sorry for late reply)
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