Question

Find the coordinates of midpoint P of BC. Then calculate lengths AP, BP, and CP.

Answer 1

you find mid poiint exactly right..now to find AP BP CP use distance formula...as

d=sqrt{(x2-x1)^2+(y2-y1)^2}

Answer 2

So, AP=sqrt{(h-0)^2+(k-0)^2}?

Answer 3

Would AP=hk?

Answer 4

What do u mean by that?

Answer 5

@zaibali.qasmi

Answer 6

AP=sqrt{h^2+k^2}

Answer 7

next../

Answer 8

nice baby...i think your daughter..??so cute bothf you///

Answer 9

So, it's not AP=h,k?

Answer 10

no..AP mean you have to find that distance..its not coordinates..its magnitued..!!

Answer 11

I'm a little confused. What would the answer be?

Answer 12

AP=sqrt{(h-0)^2+(k-0)^2}
=> AP=sqrt{h^2+k^2}

its answer.

Answer 13

So then, BP=sqrt{{h-0)^2+(k-2k)^2}
=> BP=sqrt{h^2+-k^2}

Answer 14

yes..but (-k)^2=k^2

so it will become same as that of AP...

Answer 15

Thanks, you were a lot of help!