Question

There are 8 people on the debate team. In how many ways can the coach choose 4 members to send to competition?



70

1,680

40,320

Answer 1

8!
8*7*6*5*4*3*2*1 = 40320

Answer 2

wait nevermind thats wrong

Answer 3

@somuchhomework that counts how many ways he can arrange a line of the 8 students.

Answer 4

It'd be \(\dbinom83=\dfrac{8!}{3!(8-3)!}\)

Answer 5

agreed

Answer 6

i got 112 for that though tf

Answer 7

but aren't you selecting 4 people for the team... and not 3

Answer 8

how do i do that

Answer 9

yes

Answer 10

Oh sorry, @campbell_st is right, it should be
\[\binom84=\frac{8!}{4!(8-4)!}\]

Answer 11

how do i get the answer from that?