Indefinite Integral

Question

Indefinite Integral

anonymous · Answer

attachment

solomonzelman · Answer

show what you got (it is a dirty one)

anonymous · Answer

Since I was stuck I googled the answer and got this

xapproachesinfinity · Answer

Go for it @SolomonZelman  ^_^

solomonzelman · Answer

Calculator ?

solomonzelman · Answer

Well, and how about the steps, your teacher would catch you on that !

anonymous · Answer

The problem is, it's multiple choice and the answer doesn't look like any of the solutions and the derivative of the solutions (working backwards) all have an x in the

anonymous · Answer

numerator

xapproachesinfinity · Answer

what are your thoughts @SolomonZelman

solomonzelman · Answer

By the way that calculator is bad, because it has a radical in the denominator.

anonymous · Answer

True

anonymous · Answer

Partial fractions:
$$x^4+1=(x^2-2\sqrt2x+4)(x^2+2\sqrt2x+4)$$

solomonzelman · Answer

x^4+16 you mean

anonymous · Answer

Calc BC, didn't get there or Idk if we'll get there @SithsAndGiggles

xapproachesinfinity · Answer

can we use complex numbers here, i remember that some integrals involve using
complex numbers

solomonzelman · Answer

$\normalsize\color{blue}{    x^4+16=x^4+2^4=(x^2+2^2+2x+\sqrt{2}) (x^2+2^2-2x+\sqrt{2}) }$

solomonzelman · Answer

$\normalsize\color{blue}{    x^4+16=x^4+2^4=(x^2+4+2x+\sqrt{2}) (x^2+4-2x+\sqrt{2}) }$

ganeshie8 · Answer

i think you're right, most likely its a typo http://www.wolframalpha.com/input/?i=%5Cint+x%2F%28x%5E4%2B16%29

anonymous · Answer

That's what I thought @ganeshie8  and no @xapproachesinfinity  you're only allowed to use choose one of these options

xapproachesinfinity · Answer

hmmm, what can we do beside partial fraction

xapproachesinfinity · Answer

ganesh that's the kind of integral i though about when i saw this xD

ganeshie8 · Answer

http://www.physicsforums.com/showthread.php?t=531460 looks its one of those time consuming integrals which you do for practice but is never allowed to show up in exams :o