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Mathematics 16 Online
OpenStudy (anonymous):

How many different arrangements of the letters in the word BETTER are there? 180 360 720

OpenStudy (antonio_xx2):

6*5*4*3=?/2=?

OpenStudy (anonymous):

\[\frac{6!}{2!2!}\] The \(6!\) counts the number of distinct arrangements. By distinct, I mean we consider repeated letters to be different from the other. For instance, \[BE\color{red}T\color{blue}TER~~~~~~~~BE\color{blue}T\color{red}TER\] are counted as distinct. There are two repeated letters, T and E. The 2! (one for T and one for E) remove the arrangements that are double-counted. In other words, strings like the ones above are counted only once.

OpenStudy (anonymous):

thank you man!

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