Question

is there a simpler form of 5/(tan(x)+sec(x)) ?

Answer 1

\(\bf \cfrac{5}{tan(x)}+sec(x)?\)

Answer 2

\[5/(tanx+secx)\]

Answer 3

hmm \(\bf \cfrac{5}{tan(x)+sec(x)}\implies \cfrac{5}{\frac{sin(x)}{cos(x)}+\frac{1}{cos(x)}}\implies \cfrac{5}{\frac{sin(x)+1}{cos(x)}}
\\ \quad \\
\cfrac{\frac{5}{1}}{\frac{sin(x)+1}{cos(x)}}\implies \cfrac{5}{1}\cdot \cfrac{cos(x)}{sin(x)+1}\implies\cfrac{5cos(x)}{sin(x)+1}\)

not sure if I'd caller a simplified version of it though

Answer 4

haha- yeah thats where i called it quits and came here