A bullet of 0.0500 kg is fired into a block of wood. Knowing that the bullet left the gun
with a muzzle velocity of 350. m/s, and the bullet penetrates .15 m into the block of
wood, determine:
a) The average force required to stop the bullet.
b) The impulse exerted by the wood on the bullet.

Question

A bullet of 0.0500 kg is fired into a block of wood. Knowing that the bullet left the gun 
with a muzzle velocity of 350. m/s, and the bullet penetrates .15 m into the block of 
wood, determine:
a) The average force required to stop the bullet.
b) The impulse exerted by the wood on the bullet.

anonymous · Answer

question is this two objects colliding.....?

anonymous · Answer

Force=mass times acceleration

anonymous · Answer

ANSWER FOR A)  2.0x e4 N   b) .17.5kg*m/s

i tried f=ma didnt get the right answer...

schrodingers_cat · Answer

A.

Time for the bullet to stop is d/vf = .15/(350 +0)/2 = 8.57 x 10^-4

$$\Delta p = \Sigma f \Delta t$$

f = .05(350 -0)/ (8.57 X10 ^-4) = 2 x 10^4 N

B.

I = .05(350 -0) = 17.5 kg x m/s