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OpenStudy (anonymous):
Please Help!! 2 Al(NO3)3 + 3 Na2CO3 - -------> Al2(CO3)3(s) + 6 NaNO3 If 852.04 g Al(NO3)3 reacted with the 741.93 g Na2CO3, which would be the limiting reagent ? i got that the limiting reagent is Al(NO3)3, but how many moles of Na2Co3 and Al(nO3)3 are needed
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