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Mathematics 8 Online
OpenStudy (ria23):

What is the length of the major axis of the conic section shown below? (x-3)^2/49+ (y+6)^2/100=1 A. 20 B. 14 C. 10 D. 7

OpenStudy (anonymous):

you know what this looks like?

OpenStudy (ria23):

I do not. I don't really remember this section. Conic sections went by to fast.

OpenStudy (anonymous):

yeah they always stick em at the end when there is not enough time

OpenStudy (anonymous):

in any case you don't really need to know that much for this question general form is \[\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1\] in your case \(a^2=49, a=7,b^2=100,b=10\)

OpenStudy (anonymous):

since \(b=10\) is the bigger of the two the major axis has length \(20\) i.e. \(2\times 10\)

OpenStudy (anonymous):

|dw:1407898076909:dw|

OpenStudy (ria23):

O.O is that the answer?

OpenStudy (anonymous):

like that because the larger number is under the \(y\) term

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

why would i lie?

OpenStudy (ria23):

xD Yhu don't really have a reason... I'm just wondering what the heck happened. ;o;

OpenStudy (anonymous):

not sure what you mean in your case \(b=10\) and the major axis has length double that

OpenStudy (ria23):

Ok... I'l start with... Where did yhu get the 49 and 100 from? Nevermind... the denominators... why did yhu cut 'em in half? It said squared.

OpenStudy (anonymous):

lets go slow

OpenStudy (anonymous):

general form is \[\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1\] with center \((h,k)\) you have \[\frac{(x-3)^2}{49}+\frac{(y+6)^2}{100}=1\]

OpenStudy (anonymous):

that makes the center \((3,-6)\) although you were not asked for the center

OpenStudy (anonymous):

it also make \(a^2=49\) so you know \(a=7\) and similarly \(b^2=100\) making \(b=10\)

OpenStudy (anonymous):

because the larger number is under the \(y\) term it looks like the one on the right, not the one on the left |dw:1407898559274:dw|

OpenStudy (anonymous):

you weren't asked that either, but no matter you were asked for the length of the major axis the fact that \(b=10\) tells you that the distance from the center to the vertices is 10 units, making the length of the axis 20|dw:1407898660084:dw|

OpenStudy (ria23):

Oh my god. >.< I remember this now. Yhu helped me with the same thing a while ago... but I didn't have the graph so I got confused... Yhu like... A genius. And I deem yhu my favorite mod. Thank yhu for the help. ^u^ Again.

OpenStudy (anonymous):

your welcome glad i am your fave mod

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