Question

Imagine the point (11 -8) on the terminal side of an angle. Find the value of the secant of this angle. i need help asap

Answer 1

hold on

Answer 2

secant is 1/cos

Answer 3

use a ^2 + b^2 = c^2 to find the third side

Answer 4

and then you know the hypotenuse to find cos.

Answer 5

and after finding cos. just do 1/ cos to find secant

Answer 6

i think this is right but i might be totally wrong

Answer 7

\[hypotenuse = \sqrt{11^2 + 8^2}\]
\[secant=hypotenuse/ initial side\]

Answer 8

wait hold on

Answer 9

so i think my answer is sec=sqrt(185)/11?

Answer 10

yeah!! genius. use calculator to solve it further.

Answer 11

okay thanks (: sorry it just took me little while to figure it out haha

Answer 12

np)