How do you find the maximum value of 2cos(A+10)cos(A+20)? What is the value of A which makes it a maximum
@ganeshie8 @ikram002p sorry if ur eating lol
hehe yeah lol , xD im late to breakfast brb
can we write it as below ? \[\large 2\cos(A+10)\cos(A+20) = \cos(2A+30) + \cos(10)\]
which identity?
2cosAcosB = cos(A+B) + cos(A-B)
ohhhhhh ye ok
a=30/2 ?
i need steps @dg2 i dont care what the answer is, i need to learn
idk i am asking....
rest should be easy to conclude as cos(10) is just a constant number
ok but how do i find the max value
try below : \[\large -1\le \cos(2A+30) \le 1\]
\[\large -1+\cos(10)\le \cos(2A+30) + \cos(10)\le \color{purple}{1+\cos(10)}\]
that right side bound is the max value ^^
a sin θ ± b cos θ = ±√ (a2 + b2 ) { for min. use – , for max. use + }
when we are using this formulae idk?
The question asks for the value of A that will make the expression a maximum.
thanks guise
np :) again, the question is also asking about what value(s) of A makes it maximum...
you still need to solve : \( \cos(2A+30) = 1\) for A values that give u max
ty
this problem is over ahh?
A plot and solution using Mathematica v9 is attached.
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