The table below shows the distance d(t) in feet that an object travels in t seconds:

t
(second)

d(t)
(feet)

2

64

4

256

6

576

8

1024

What is the average rate of change of d(t) between 2 seconds and 6 seconds, and what does it represent?

Question

The table below shows the distance d(t) in feet that an object travels in t seconds:




t 
(second) 

d(t) 
(feet) 


2 

64 


4 

256 


6 

576 


8 

1024 



What is the average rate of change of d(t) between 2 seconds and 6 seconds, and what does it represent?

anonymous · Answer

please help medal wil be rewarded

sidsiddhartha · Answer

average rate of change of d(t)=$$\frac{ 576-6 }{ 64-2 }$$
solve it
AND it represents the average speed of the object between 2 seconds and 6 seconds.

anonymous · Answer

thank you!!!!!!!!!!!

xapproachesinfinity · Answer

it should be the opposite
d(t)/t not like @sidsiddhartha

xapproachesinfinity · Answer

wrote

xapproachesinfinity · Answer

average speed = distance traveled divided by time

xapproachesinfinity · Answer

So $\huge \frac{576-64}{6-2}$ i think he did a typo lol

anonymous · Answer

that make more sense thank you so much @xapproachesinfinity

xapproachesinfinity · Answer

$\huge you~ are~welcome!$

sidsiddhartha · Answer

lol yeah the pattern made it a bit confusing :)