How many liters of a 2.25 molar hydrobromic acid (HBr) solution would be needed to react completely with 100.0 grams of calcium metal? Ca(s) + 2HBr (aq) yields CaBr2 (aq) + H2 (g) 1.11 liters 2.22 liters<--- My answer 2.81 liters 225 liters Can anyone please check this for me? @hartnn @SolomonZelman @cwrw238 @Abhisar
Yes that's \(\huge\checkmark\)
Thank you so much!!!
Can I plz get a medal?
No !
oh ok sorry
I was about to give u one by myself but u asked for it.
oh I apologize
It's ok :)
so i got one? @Abhisar
yes i already gave u one O_O
LOL sorryyy i'm kinda new to this but thank u for ur time and help
\(\rlap{\color{blue}{\huge\bigstar}\huge \color{blue}{ \text{You're Most Welcome! }}\color{blue}\bigstar}{\; \color{aqua}{\huge\bigstar}\huge \color{aqua}{\text{You're Most Welcome! }}\color{aqua}\bigstar}\) \(~~~~~~~~~~~~~~~~~~~~~~~~~~~\color{green}{\huge\ddot\smile}\color{blue}{\huge\ddot\smile}\color{pink}{\huge\ddot\smile}\color{red}{\huge\ddot\smile}\color{yellow}{\huge\ddot\smile}\)
wow that is cool!
:)
\(\Huge\frak\rlap{\color{black}{\heartsuit~Welcome~to~OpenStudy!~\heartsuit}}{\color{red}{\; \heartsuit~W}\color{gold}{e}\color{lime}{l}\color{cyan}{c}\color{blue}{o}\color{purple}{m}\color{blueviolet}{e~}\color{magenta}{t}\color{orchid}{o~}\color{red}{O}\color{gold}{p}\color{lime}{e}\color{cyan}{n}\color{blue}{S}\color{purple}{t}\color{purple}{u}\color{purple}{d}\color{purple}{y}\color{purple}{!}\color{blueviolet}{\heartsuit}}\)\(\hspace{-270 pt}\Huge\color{red}{^*:}\color{gold}{_・゚}\color{lime}{^✧}\color{cyan}{_*}\color{blue}{:}\color{purple}{^・゚}\color{blueviolet}{_✧}\color{magenta}{^*}\color{orchid}{:}\color{red}{_・゚}\color{gold}{^✧}\color{lime}{_*}\color{cyan}{:}\color{blue}{^・゚}\color{purple}{✧}\)
i also have one more question is that ok?
yes ask it in a new post
WOW! i love OPENSTUDY! haha thank you
ok
Please be a lill quick :)
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