Question

what is 0 times 1/0?

Answer 1

0 times 1 is 0 / 0 = 1 ?

Answer 2

1/0 is undefined so if you multiply it by 0 it will remain undefined

Answer 3

syntax error

Answer 4

Error!

Answer 5

lol

Answer 6

1/0 is undefined for sure, and 0/0 is on some level equivalent to 1.
So when you say `0 × (1/0)` you are multiplying the number that is for sure undefined by 0.

Answer 7

0/0 can be 1 or undefined
0/1 can ONLY be UNDEFINED

Answer 8

For your question, just put "undefined"

Answer 9

ok thank you but so your saying it can also be 1?

Answer 10

haha

Answer 11

Well, on some level. It is very complicated. You can sa that 0/0 is any number technically, because when you look at `0/0 = d/1` and cross multiply, you get ` 0 × d = 0 × 1` which gives `0=0`. See my point?

Well, it is fair to say though, that UNDEFINED is the BEST answer.

Answer 12

So when you prove from 0/0=d/1 you can say that d is any number, in other words it is undefined, just because it can be any number.

Answer 13

it can be ∞

Answer 14

ok thanks so much for explaining it so well. I was asking this question because i was looking a somones anser on open study for my real question and if you want to help me a little more if you can take a look at this link. scroll down to scrollpatrols anser : http://openstudy.com/study#/updates/52de7fbce4b003c643a11055

Answer 15

it involves the question 0 times !/0

Answer 16

It can't be ( 0 × ! ) / 0 it has to be a factorial of something, or

0! / 0 perhaps ?

Answer 17

0! / 0 is same as 1/0, because 0! is defined to be 1.

Answer 18

oh ok so do you think that he used a good example on explaining the question?

Answer 19

Well, saying that 0 × (1/0) = 1
if you cancel the top and above zero, but there is a rule that `anything times zero, is equivalent to zero`
I can sort of agree with canceling the denominator with the number you multiply by (which in this case is a zero), but I really do not relate multiplying anything times 0/1?
Because
0/1 × 0 is same as 'undefined' × 0, and shouldn't be equal to zero or 1.

I would say use the one I sad about 0/0 = d/1 (because 0/0 is at least somehow a number)

But try it for 0/4. If you have 0 pizza slices, and 4 friends, and you
distribute those 0 pizza slices (you're feeling generous...) equally
amongst each of them, how much would each of your 4 friends get?
Clearly, they would each get 0 dollars!

Now try it for 4/0. If you have 4 pizza slices and 0 friends, and you....
but how can you distribute any amount of money amongst friends who
don't exist? So the question of what 4/0 means makes no sense!

Answer 20

bottom line, 0/0 and 0/1 are both undefined.

Answer 21

Another way: 0/0 (like distributing 0 piece of cakes amongst 0 friends), so you can have this equivalent to any number, because you just not distributing anything to anyone.

so, 0/0=15 check it, 15 × 0 =0 Nope, check doesn't work. Extraneous solution :)

Answer 22

same way 0/0 can be equal to any negative or positive real number. And perhaps even to an imaginary number.

Answer 23

ok thank you so much. now i just have to figure out which example i want to use to slove my original question about kelly

Answer 24

Original question about Kelly ?

Answer 25

its the question that i posted the link to. That my original question that i need to slove

Answer 26

`Kelly tells you that when variables are in the denominator, the equation becomes `
`unsolvable. "There is a value for x that makes the denominator zero, and you can't`
` divide by zero," Kelly explains. Using complete sentences, demonstrate to Kelly `
`how the equation is still solvable.`

There is a value of a variable that makes a denominator equal zero, and this value is called a restriction. IF this variable is x, then it is a domain restriction, and if it y or f(x) then it is a range restriction.

You don't want to have 0/0 because it is undefined.

She is wrong however in her first line, because if there is a variable in a denominator, then there will be a restriction, but there will be a solution.

You can solve the equation (last sentence), however it depends on the equation if it will have x (or y) intercept(s) .

Answer 27

oh ok im kinda getting it. so when it is asking me that it is solvable i would say that it depends on the equation if it will have x(ory) intercepts?

Answer 28

Yes, you would say that it is typically solvable.
(by the 'solutions' they are probably referring to x-intercept(s) )

Answer 29

so they are saying to demonstrate to kelly that it is solvable

Answer 30

They are asking you to explain it in general i.e. without using any specific example. (Which is harder)

Answer 31

You should propose some explanation/theory to this.

Answer 32

Well, if Kelly had a different equations that SHE was asking about, then you would show it on this equation.

Answer 33

yeah your right. ok i think ill put something together to anser the question. Thanks so much for your time and patients and your help. (:

Answer 34

Anytime ! enjoy ;)