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Mathematics 17 Online
OpenStudy (anonymous):

CAN ANYONE HELP ME PLSSSSSSSSSSSSSS?????!!!!!

OpenStudy (anonymous):

The temperature of a chemical reaction ranges between 20°C and 160°C. The temperature is at its lowest point when t = 0, the temperature is 90 degrees and increasing and completes one cycle over an eight-hour period. What is a sine function that would model this reaction?

OpenStudy (anonymous):

i can

OpenStudy (anonymous):

f(t) = 90 sin pi over 4t + 70 f(t) = 70 sin pi over 4t + 90 f(t) = 70 sin 8t + 90 f(t) = 90 sin 8t + 70

OpenStudy (anonymous):

help you yourself

OpenStudy (anonymous):

The amplitude and vertical shift can be found with the temperatures given 160°C − 20 = 140°C 140°C / 2 = 70°C The amplitude's 70 70°C + 20 = 90°C The vertical shift's 90 You'll have to divide 360° by the 8 hours to find the period 360 / 8 = 45 Normally the horizontal shift would be 90° to the right, since this starts at the 270° point in the function, but because the period's 8 instead of 360° it's 8 / 4 = 2° y = 70 sin(45(x − 2°)) + 90 y = 70 sin(45x − 90°) + 90

OpenStudy (anonymous):

That doesn't work, @A.K.C.15

OpenStudy (anonymous):

I don't know what to do after the last equation

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