Question

an=n^3/(n-1)!....write the first four terms of the sequence whose general term is given?...please help

Answer 1

put n = 0, 1, 2,3 and 4 in the general equation...

Answer 2

n = 1,2,3,4

for first term we get 0! as the denominator

do you know value of 0! ?

Answer 3

is it 3?

Answer 4

0! = 1

so first term = 1^3 / 1 = 1

Answer 5

2nd term = 2^3 / (2-1)!

Answer 6

then plug in 3 and 4 into the general formula

Answer 7

Am getting 1/12, but am not sure am right

Answer 8

sorry, that was a different question

Answer 9

1/0, 8/0, 27/2, 32/3 ..... is that correct?

Answer 10

no

as i said 0! = 1
so first term is 1^3 / 1 = 1
second = 2^3 / 1! = 8/1 = 8

Answer 11

do you now what n! means? pronounced n factorial

Answer 12

number? or general term

Answer 13

its best explained by an example

3! = 3*2*1

6! = 6*5*4*3*2*1

- just keep multiply down to the number 1

Answer 14

so the 3rd term is 3^3 / (3-1)! = 27/2! = 27 / 2*1 = 27/2 or 13.5

Answer 15

ok?

Answer 16

ok...am now getting it

Answer 17

Thanks a million

Answer 18

so can you work out the 4th term?

Answer 19

yw

Answer 20

32/3 right?

Answer 21

4^3 / (4 -1)! = 64 / 3! = 64 / 6 = 32/3
yes

Answer 22

gotta go right now

Answer 23

wow... now i get it

Answer 24

byee, thanks for your help