well its simply
\[\sqrt{\frac{3x^{12}y^{10}}{5x^6y^3}}\]
subtract the powers.... to simplify
OpenStudy (anonymous):
\[\large \frac{x^m}{x^n} = x^{m-n}\]
OpenStudy (anonymous):
x^6
and
y^7
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OpenStudy (campbell_st):
so you'll end up with
\[\sqrt{\frac{3x^6 y^7}{6}} = \frac{\sqrt{3(x^3)^2 (y^3)^2 \times y}}{\sqrt{6}} = \frac{x^3y^3\sqrt{3y}}{\sqrt{6}}\]
that's my best guess
OpenStudy (campbell_st):
oops denominator should be 5
OpenStudy (anonymous):
Hmm.
Well here's my choices
OpenStudy (campbell_st):
can you check your question is is 3x^12y^10
or 15x^12y^10
OpenStudy (anonymous):
It's a 3 not a 15.
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OpenStudy (campbell_st):
ok... they have rationalised the denominator... which means that took
\[\frac{x^3 y^3 \sqrt{3y}}{\sqrt{5}} \times \frac{\sqrt{5}} {\sqrt{5}} = \frac{x^3y^3\sqrt{15y}}{5}\]