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Mathematics 9 Online
OpenStudy (anonymous):

Simplest form of quotient radicals

OpenStudy (anonymous):

\[\large \frac{ \sqrt{3x^{12}y^{10}} }{ \sqrt{5x^{6}y^{3}} }\]

OpenStudy (anonymous):

@campbell_st

OpenStudy (campbell_st):

well its simply \[\sqrt{\frac{3x^{12}y^{10}}{5x^6y^3}}\] subtract the powers.... to simplify

OpenStudy (anonymous):

\[\large \frac{x^m}{x^n} = x^{m-n}\]

OpenStudy (anonymous):

x^6 and y^7

OpenStudy (campbell_st):

so you'll end up with \[\sqrt{\frac{3x^6 y^7}{6}} = \frac{\sqrt{3(x^3)^2 (y^3)^2 \times y}}{\sqrt{6}} = \frac{x^3y^3\sqrt{3y}}{\sqrt{6}}\] that's my best guess

OpenStudy (campbell_st):

oops denominator should be 5

OpenStudy (anonymous):

Hmm. Well here's my choices

OpenStudy (campbell_st):

can you check your question is is 3x^12y^10 or 15x^12y^10

OpenStudy (anonymous):

It's a 3 not a 15.

OpenStudy (campbell_st):

ok... they have rationalised the denominator... which means that took \[\frac{x^3 y^3 \sqrt{3y}}{\sqrt{5}} \times \frac{\sqrt{5}} {\sqrt{5}} = \frac{x^3y^3\sqrt{15y}}{5}\]

OpenStudy (anonymous):

That was right thank you!!

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