Question

Please help! Solve -3x2 - 4x - 4 = 0.

x equals quantity of 2 plus or minus 4i square root of 2 all over 3

x equals quantity of 2 plus or minus 2i square root of 2 all over 3

x equals quantity of negative 2 plus or minus 2i square root of 2 all over 3

x equals quantity of negative 2 plus or minus 4i square root of 2 all over 3

Answer 1

\[-3x ^{2}-4x-4=0\]
make sure x^2 is positive by multiplying everything by -1 to get
\[3x ^{2}+4x+4=0\]
Do you know how to factor out? @ibreezysaan

Answer 2

No, sorry ): I'm not really good at it @Mokeira

Answer 3

do you know quadratic formula?

Answer 4

\[ -3x2 - 4x - 4 = 0\\
3x^2+4x-4=0\] then the quadratic formula
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] with
\[a=3,b=4,c=-4\]

Answer 5

lol..i was actually kinda stuck. @satellite73

Answer 6

so far, \[-4\pm \sqrt{16+48}/2a\]

Answer 7

what do i do next? @satellite73

Answer 8

a=3
be sure to substitute that too

Answer 9

that would be 6.... so, what now?

Answer 10

\[-4\pm \frac{ \sqrt{64} }{ 6 }\]
find square root of 64