Please, please help me fast, fast, fast!
If 4.8 moles of X and 3.4 moles of Y react according to the reaction below, how many moles of the excess reactant will be left over at the end of the reaction? 3 X + 2Y --> X3Y2 A) 1.7 mol Y left over B) 1.6 mol X left over C) 0.2 mol Y left over D) 0.1 mol X left over
compare the moles you have to the molar ratio from the balanced reaction.
the balanced reaction says 3X:2Y
Normally on these you just subtract or work it out like a math problem, but you can't do that on this one.. The ratio is 3:2, right?
you HAVE 4.8X:3.2Y. Does that equal 3:2?
Yes.
check again
sorry, should be 3.4 moles of Y
Well, I'm better at math. In my head they were both divisible by 1.6. So no, I guess for this they are not.
4.8X:3.4Y is not the same ratio as 3X:2Y
if you multiply 3.4 by 1.5, what do you get?
Oh, that makes more sense. Lol. 5.1
do you have 5.1 moles of X? No, you've only got 4.8. So which is the limiting reactant?
X?
it is. Now how much Y will be used when all the X is used up?
3.4?
multiply the limiting reactant by the mole ratio
7.2?
\[ 4.8 moles X * \frac{2 moles Y used}{3 moles X used}\]
Oh, oops. 3.2!
exactly
so using 4.8 moles of X will also use 3.2 moles of Y
You HAVE 3.4 moles of Y available, and will USE 3.2 moles. How much is left over?
Oh, got it. So that's the excess, and we will have 0.2mol left overrrr. Yay. Thank you so much! God bless youuuu! <3
not god, science ;-)
Jeeeesus. And that's a capitol G, sirrr.
if it makes you happy
answer is 0.2 mole of Y left over
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