According to data from the U.S. Bureau of the Census, the approximate population y (in millions) of Los Angeles between 1950 and 2000 is given by 0.0000113x^3 -0.000922x^2 +0.0538x +1.97 where 0 corresponds to 1950. Determine the year in which the population of Los Angeles reached 2.6 million.
There are no results. Trust me; I've already tried google. XD
If it helps anyone, I know the answer is 1964.
Honestly I have no clue that is why I tried to google it for you, but hey maybe @abb0t can help you he is great at helping people. :)
Can you use software lol? These look like really ugly numbers to work with by hand
http://www.wolframalpha.com/input/?i=2.6%3D0.0000113x%5E3+-0.000922x%5E2+%2B0.0538x+%2B1.97
I believe so!
x = 14.773. Since the baseline x =0 is considered 1950, then 1950+14.773 = 1964 (about)
which makes sense, the population attained 2.6 million sometime during 1964, but before 1965
Where on the graph is the 2.6 million concerned?
Don't get me wrong; what you have said does make sense. It's just that I don't know how 14.773 and 26 million are related. I don't know. Maybe I'm just have a brain-malfunction or something. -.-
You know that y = 2.6 is what you are looking for But in general, y = 0.0000113x^3 -0.000922x^2 +0.0538x +1.97 So the equation you are solving for is 2.6 = 0.0000113x^3 -0.000922x^2 +0.0538x +1.97 When you solve this, it gives you x = 14.77 , where "x" is the year But the baseline is indicated to be 1950, so i added 14.77 to 1950
does it make sense
Oh yes, it does now. Thank you so much for the help and explanation. :D
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