2x - 12 = 3y 5x + 4y = 7 Help me with Gaussian substitution please! Work me through it. I want to understand.
@precal
@SolomonZelman @Zale101 @zepdrix
Hey c: So we're doing the substitution method, not the elimination method?
My teacher said it's Gaussian subst. where you have to multiply each side by a number then cancel out a pair of numbers.
Oh ok, we call that Gaussian Elimination, then we follow it up with back substitution. If your teacher is calling it that though, no big deal.
Nope my mistake, I wrote it wrong in my notes haha
Oh hehe. \[\Large\rm 2x - 12 = 3y\]\[\Large\rm 5x + 4y = 7\]We need all of our x's and y's on the same side. In equation #1, let's subtract 3y from each side, and add 12 to each side.
\[\Large\rm 2x - 3y = 12\]\[\Large\rm 5x + 4y = 7\]Understand that first step ok? :o
Yes! That's the part I couldn't understand was moving the variables around.
I think I can work it myself. I'll try.
Hmm ok cool :) Yah give it a shot.
Is the solution (3, -2) ? @zepdrix
Ooo yay! Nice job!
Thank you! I appreciate it very much!
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