a student is instructed to make 1L of a 2 M solution of CaCl2 using dry salt how should he do this?

Question

anonymous · Answer

@JoannaBlackwelder

ipwnbunnies · Answer

$$Molarity = \frac{moles of solute}{liters of solvent}$$

ipwnbunnies · Answer

$$2 M = \frac{moles of CaCl2}{1 L}$$
How many moles of CaCl2 would you need?
I think that's what you're asking

anonymous · Answer

yea is it 222 g of cacl2

anonymous · Answer

@iPwnBunnies

anonymous · Answer

like use up 222 g and then do the rest for the 1 L

ipwnbunnies · Answer

Correct. 
You need 2 moles of CaCl2 for a molarity of 2 M.

The molar mass of CaCl2 is 110.9 grams per moles.

(2 moles)*(110.9 grams per mole) ≈ 222 grams

anonymous · Answer

ok i understand thanks a bunch!!!