Question

why is dx/dy of (2x-3x^2)^5 = 12x^5 (1-3x) (2-3x)^5

Answer 1

this is what i got

(6) (-6x+2) (2x-3x^2)^5

=12(1-3x) (2x-3x^2)^5

Answer 2

you mean \(\dfrac{dx}{dy}\) ? and \(y = (2x-3x^2)^5\), right?

Answer 3

right

Answer 4

Remember \(\dfrac{dx}{dy}\neq \dfrac{dy}{dx}\)

Answer 5

so that, if you have y w.r.t x, then dx/dy = 1/(dy/dx)

Answer 6

sorry i meant dy/dx

Answer 7

thanks for noticing

Answer 8

ok. hihihi

Answer 9

Use the chain rule. Deal with the exponent of 5 first, then what's inside the parenthesis next.

Answer 10

could u please explain it to me?

Answer 11

I think OOPS left.

Answer 12

Oh sure, I would be honored.

Answer 13

what am i supposed to do after this:

= (6) (-6x+2) (2x-3x^2)^5

=12(1-3x) (2x-3x^2)^5