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Chemistry 13 Online
OpenStudy (anonymous):

A solution of HCl has [H+] = 0.01 M. What is the pH of this solution? –2 –1 1 2

OpenStudy (joannablackwelder):

pH=-log[H+]

OpenStudy (anonymous):

nooo xD not this stuff again xD should know lol

OpenStudy (joannablackwelder):

Can you substitute and simplify? This one is already solved for pH.

OpenStudy (joannablackwelder):

haha, yup, this again.

OpenStudy (anonymous):

kk so,...

OpenStudy (anonymous):

-2=-log[0.01] ?

OpenStudy (joannablackwelder):

Hold on, where did the -2 come from?

OpenStudy (anonymous):

the ph at the bottom i was plugging it in

OpenStudy (joannablackwelder):

Those are the answer choices. We don't know which one is right yet, so let's hold off on looking at those.

OpenStudy (anonymous):

kk

OpenStudy (joannablackwelder):

So, pH=-log[0.01] Right?

OpenStudy (anonymous):

yes

OpenStudy (joannablackwelder):

:)

OpenStudy (joannablackwelder):

Can you simplify the log side (you will need to use a calculator).

OpenStudy (anonymous):

1.02329299

OpenStudy (anonymous):

- in front my bad

OpenStudy (joannablackwelder):

Are you sure you used the common log?

OpenStudy (joannablackwelder):

Not the natural log (ln)?

OpenStudy (anonymous):

not sure you said log was 10^0.01 right

OpenStudy (joannablackwelder):

No, that is "undoing" the log to solve for the concentration.

OpenStudy (joannablackwelder):

But this problem we have the concentration.

OpenStudy (joannablackwelder):

You need to use the log button on your calculator this time.

OpenStudy (joannablackwelder):

Take the log of 0.01

OpenStudy (joannablackwelder):

It should be a button that says "log"

OpenStudy (anonymous):

ohhh

OpenStudy (joannablackwelder):

:)

OpenStudy (anonymous):

so it is -2

OpenStudy (joannablackwelder):

Right, log(0.01) is -2

OpenStudy (joannablackwelder):

So, pH=-(-2)

OpenStudy (anonymous):

so it is 2?

OpenStudy (joannablackwelder):

:D

OpenStudy (anonymous):

So D.

OpenStudy (joannablackwelder):

Yup

OpenStudy (anonymous):

Thanks ;D

OpenStudy (joannablackwelder):

No worries

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