Chemistry
13 Online
OpenStudy (anonymous):
A solution of HCl has [H+] = 0.01 M. What is the pH of this solution?
–2
–1
1
2
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OpenStudy (joannablackwelder):
pH=-log[H+]
OpenStudy (anonymous):
nooo xD not this stuff again xD should know lol
OpenStudy (joannablackwelder):
Can you substitute and simplify? This one is already solved for pH.
OpenStudy (joannablackwelder):
haha, yup, this again.
OpenStudy (anonymous):
kk so,...
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OpenStudy (anonymous):
-2=-log[0.01] ?
OpenStudy (joannablackwelder):
Hold on, where did the -2 come from?
OpenStudy (anonymous):
the ph at the bottom i was plugging it in
OpenStudy (joannablackwelder):
Those are the answer choices. We don't know which one is right yet, so let's hold off on looking at those.
OpenStudy (anonymous):
kk
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OpenStudy (joannablackwelder):
So, pH=-log[0.01]
Right?
OpenStudy (anonymous):
yes
OpenStudy (joannablackwelder):
:)
OpenStudy (joannablackwelder):
Can you simplify the log side (you will need to use a calculator).
OpenStudy (anonymous):
1.02329299
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OpenStudy (anonymous):
- in front my bad
OpenStudy (joannablackwelder):
Are you sure you used the common log?
OpenStudy (joannablackwelder):
Not the natural log (ln)?
OpenStudy (anonymous):
not sure you said log was 10^0.01 right
OpenStudy (joannablackwelder):
No, that is "undoing" the log to solve for the concentration.
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OpenStudy (joannablackwelder):
But this problem we have the concentration.
OpenStudy (joannablackwelder):
You need to use the log button on your calculator this time.
OpenStudy (joannablackwelder):
Take the log of 0.01
OpenStudy (joannablackwelder):
It should be a button that says "log"
OpenStudy (anonymous):
ohhh
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OpenStudy (joannablackwelder):
:)
OpenStudy (anonymous):
so it is -2
OpenStudy (joannablackwelder):
Right, log(0.01) is -2
OpenStudy (joannablackwelder):
So, pH=-(-2)
OpenStudy (anonymous):
so it is 2?
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OpenStudy (joannablackwelder):
:D
OpenStudy (anonymous):
So D.
OpenStudy (joannablackwelder):
Yup
OpenStudy (anonymous):
Thanks ;D
OpenStudy (joannablackwelder):
No worries