Question

Derive the equation of the parabola with a focus at (−2, 4) and a directrix of y = 6. Put the equation in standard form.

Answer 1

I Just Need Answers Lol Need 2 Turn This In Like Now Teacher On My retrice

Answer 2

vertex should be at \((-2,5)\) so you know it looks like
\[4p(y-5)=(x+2)^2\] and all you need is \(p\)

Answer 3

\(p\) is the distance from the focus to the vertex which is pretty clearly \(1\) and this parabola opens down
form is
\[-4(y-5)=(x+2)^2\]

Answer 4

we can check it if you like

Answer 5

Is That Supposed 2 Be The Answer?
The -4(y-5) One

Answer 6

\[-4(y-5)=(x+2)^2\]

Answer 7

check it here
http://www.wolframalpha.com/input/?i=parabola+-4%28y-5%29%3D%28x%2B2%29^2

Answer 8

Thats Not A Answer Choice
These Are...
f(x) = one fourthx2 − x + 4

f(x) = −one fourthx2 − x + 4

f(x) = one fourthx2 − x + 5

f(x) = −one fourthx2 − x + 5

Answer 9

then solve \[-4(y-5)=(x+2)^2\] for \(y\)

Answer 10

Man Im Lost