2 g of iron (III) oxide is reacted with 0.2 g of carbon according to: Fe2O3 + 3 C -> 2 Fe + 3 CO Determine the mass of iron (in g) produced.
Can you determine which one is limiting?
So far I have calculated n(Fe2O3)=2/159.7=0.125 mol n(C)=0.2/12.01=0.0167 mol N(C)needed=0.0125mol(Fe2O3)x3mol(C)/1mol(Fe2O3)=0.0375 as there is only 0.0167molC available and 0.0375mol is needed then C is the limiting reagent. after that I used the molC available to determine the mass Fe produced: 0.-167x1/3x159.687/1=0.8889g but the answer was wrong so I dont think I am doing it right.
Carbon is limiting :)
Only the last step is the issue. The question is asking for grams of Fe, not iron oxide.
Can you help me to determine where I am going wrong?
0.0167 mol C (2 mol Fe/3 mol C) * (55.8 g Fe/1 mol Fe)
oh Duhh!!! Omg how did I not see that!
Haha, no worries. It happens to the best of us.
It would have been right if you were looking for iron oxide ;)
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Yeah fail! Thank you so much!
No worries. Happy studies!
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