Question

Jacob kicks a soccer ball off the ground and in the air, with an initial velocity of 33 feet per second. Using the formula H(t) = -16t2 + vt + s, what is the maximum height the soccer ball reaches?

15.1 feet

16.5 feet

17.0 feet

18.2 feet

Answer 1

the maximum height = the vertex Y value

Answer 2

is the ANSWER C?

Answer 3

we cant just give away answers and id have to check first

Answer 4

CAN U CHECK PLS

Answer 5

im assuming the v=33ft/s

Answer 6

not sure what the s means

Answer 7

Hey, I have flvs too! are you in shkoler's class?

Answer 8

WHY

Answer 9

im not i have a diff teacher

Answer 10

have u done this before

Answer 11

are you sure its + s? or + 5

Answer 12

aw boo, I'm not done yet, which teacher do you have?

Answer 13

idk i copied and pasted this

Answer 14

i forgot her name but what module are you on

Answer 15

you forgot your teacher's name?

Answer 16

yeah sorta what module u on

Answer 17

H(t) = -16t^2 + vt + s
"Jacob kicks a soccer ball OFF THE GROUND" implies the initial height of the ball is 0.
v = 33 feet per second.
h(t) = -16t^2 + 33t ----- (1)
Maximum height is reached at the vertex.
t at the vertex = -b/2a = -33/(2*(-16)) = 33/32 sec.
plug t = 33/32 into (1) and find the max height.

Answer 18

Initial height of the ball s = 0.

Answer 19

ya thats what i figured

Answer 20

what s the answer

Answer 21

no

Answer 22

plug t = 33/32 into h(t) = -16t^2 + 33t and find h(t)

Answer 23

i got 17