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Chemistry 8 Online
OpenStudy (anonymous):

What mass of oxygen is contained in 5.5g of KClO3, and how many atoms of oxygen are there in this mass?

OpenStudy (joannablackwelder):

Can you find the moles of KClO3?

OpenStudy (anonymous):

Yes. I worked it out this way but I am not sure if it right. Number of moles of KClO3 =\[\frac{ mass of KClO3 }{ molar mass of KClO3 }\] =\[\frac{ 5.5g }{ 122.64 }\] = 0.045

OpenStudy (joannablackwelder):

Awesome! That's what I get.

OpenStudy (joannablackwelder):

Now, how many moles of O are there in 1 compound?

OpenStudy (anonymous):

I suppose I have to work out the mole ratio, right? K : Cl : O 1 : 1 : 3 x 0.045 Hence 0.135 moles of O

OpenStudy (joannablackwelder):

Sweet!

OpenStudy (joannablackwelder):

Now, can you convert to mass of oxygen from moles of oxygen?

OpenStudy (joannablackwelder):

Hint* you need the molar mass

OpenStudy (anonymous):

0.135mol x16g =2.16. Is that right?

OpenStudy (joannablackwelder):

That's what I get :)

OpenStudy (joannablackwelder):

Do you know how to do the second part?

OpenStudy (abhisar):

39.17 % of oxygen is contained in KClO3 molecule

OpenStudy (joannablackwelder):

The question asked for mass, not mass percent...

OpenStudy (abhisar):

39.17% of 5.5 g = 2.16 g

OpenStudy (abhisar):

By this way u can do it quickly

OpenStudy (joannablackwelder):

From moles of O you can use Avogadro's number to find number of atoms.

OpenStudy (anonymous):

I am not sure how to do the second part, I need help please!

OpenStudy (abhisar):

Calculate the moles of O [by dividing 2.16 by atomic mass of O] and then multiply the result by Avagadro number

OpenStudy (joannablackwelder):

0.135 mol O * (6.022x10^23 atoms O/1 mol O) = ? atoms O

OpenStudy (anonymous):

0.135 mol x 6.02x10^23 = 8.127x10^22 atoms of oxygen

OpenStudy (abhisar):

\(\huge\checkmark\)

OpenStudy (abhisar):

Everything clear now ?

OpenStudy (joannablackwelder):

Perfect! :)

OpenStudy (anonymous):

Thank you very much Abhisar and Joanna.

OpenStudy (abhisar):

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OpenStudy (abhisar):

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OpenStudy (joannablackwelder):

No worries :)

OpenStudy (anonymous):

If were possible for me I would voted for both answers. You have tremendously helped me you both.

OpenStudy (abhisar):

ahhan..! It's okay..glad to help :)

OpenStudy (abhisar):

@JoannaBlackwelder deserved it more :)

OpenStudy (joannablackwelder):

Thanks, @Abhisar for your help too! :)

OpenStudy (abhisar):

No problem :)

OpenStudy (anonymous):

\[Numbber of moles of KClO3=\frac{ mass of KClO3 }{ Molar mass of KClO3 }\ =\frac{ 5.5g }{ 122.64g/mol }\] = 0.045moles mole ratio; K : Cl : O 1 : 1 : 3 number of moles O2 atoms = 0.045 x 3 = 0.135 moles Mass of O2 in 5.5g of KClO3 = mole x molar mass = 0.135 x 16g = 2.16g Number of O2 atoms = 0.135 x 6.02x10^23 = 8.127x10^22

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