Question

Help check and with answers

Answer 1

first one is right
in the second one A and D are true since \(\sqrt{8}=\sqrt{4\times 2}=\sqrt4\sqrt2=2\sqrt2\) and D true for the same reason

Answer 2

thank you @satellite73

Answer 3

yw

Answer 4

may you help me with those

Answer 5

lol method or answers?

Answer 6

method

Answer 7

look for a perfect square in the radicand (the number inside the radical)
or if you don't see one factor the radicand in to a product of primes

Answer 8

the first one is the hardest
\[1008=16\times 9\times 7\] which is not so obvious

Answer 9

so
\[\sqrt{1008}=\sqrt{16}\sqrt{9}\sqrt{7}=4\times 3\times \sqrt7=12\sqrt7\]

Answer 10

second on is much easier since it should be pretty clear that \(32=16\times 2\) and so
\[\sqrt{32}=4\sqrt2\]

Answer 11

@satellite73 Why are you helping him on test questions?! I thought that's against Open Study Rules..

Answer 12

well im a girl 1st off and 2nd these are pretest questions like homework not going to affect my grade