Write the quadratic function in vertex form. y=x^2+4x+7
now, do you know what the vertex form is?
I did at one point in my life. Not so much anymore.
Wait, no. It's y = a(x – h)^2 + k, right?
Yes, that's correct.
y = a(x – h)^2 + k y = 1(x - h)^2 + k h and k represent the vertex.
Alright, I basically just need a step-by-step to let me know what I need to do and how to do it so I can figure out the problem.
h is the x-value k is the y-value
I just graph the equation and get the vertex, it takes to long to do it by hand.
The vertex is -2, 3
So we have: y = a(x - -2)^2 + 3 which equals: y = a(x + 2)^2 + 3
a = 1 (Hint: It's in the form of ax^2 + bx + c)
So our final answer is: y = 1(x + 2)^2 + 3
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Alright! I got it now. I used to be able to do it pretty well but lost my skills a little. Thank you!
Np.
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