In what ways can horizontal, vertical, and oblique asymptotes be identified?
what lesson is that, if u take flvs.
@SithsAndGiggles
nvm found it.
Its my DBA mod 5
First, you could identify if it is a horizontal asymptote is if the degree in the numerator is less then the degree in the denominator.
okay
You could find a vertical asymptote by setting the denominator equal to zero.
for oblique, you would just divide the numerator by the denominator (using any method of your desire) and the answer to that division is your oblique asymptote (do NOT include the remainder)
Im taking algebra 2 on flvs as well. Notes ftw.
ohhh haha do you think you could help with one more then?
Sure.
I attached it :)
Ok, ima do work.
Oh , the step, nvm
First, you would use KFC (keep the first fraction the same, flip the second one, and change division to multiplication)
From their, you would factor the common terms between the numerator of the first fraction and the denominator of the second fraction. Then, find the other common factors between the first denominator and second numerator.
Then, you would cancel out all of the common terms, leaving the other half of them. From their, you would multiply and that's it.
THANK YOU SOOOOO MUCH!!! :)
nm
np* i SUCK AT TYPING *:/
don't I have to include the simplified equation? @Flashy32
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