When two atoms of
2
H (deuterium) are fused to form one atom of
4
He (helium), the total energy
evolved is 3.83 × 10
-12
joules. What is the total change in mass (in kilograms) for this reaction?

Question

When two atoms of
2
H (deuterium) are fused to form one atom of
4
He (helium), the total energy
evolved is 3.83 × 10
-12
joules. What is the total change in mass (in kilograms) for this reaction?

anonymous · Answer

Please just give me the equation I need to use with the values plugged in, that's all I need.

anonymous · Answer

@Abhisar

jfraser · Answer

use $E = mc^2$  Rearrange to solve for m, then plug in the energy and speed of light

anonymous · Answer

m = E/c^2
m = 3.83 x 10^-12/c^2
how do I find c^2?

jfraser · Answer

c is the speed of light

jfraser · Answer

square it

anonymous · Answer

8.98755179 × 10^16 m^2/s^2

anonymous · Answer

things are starting to come together...lmao
m = E/c^2 m = 3.83 x 10^-12/8.98755179 × 10^16 m^2/s^2

jfraser · Answer

$ 9*10^{16} \frac{m^2}{s^2}$ would be enough

jfraser · Answer

but yes

anonymous · Answer

4.3 x 10^-29

anonymous · Answer

Thank you! I now understand it completely! :D :happydance:

jfraser · Answer

the last 4 questions you've asked have all been about $E = mc^2$ just moving the pieces around

jfraser · Answer

there's really only 2 things to find: E or m, since c is always the speed of light

anonymous · Answer

I see that now, yeah. Now all the pieces are clicking. :D