Question

What are the possible numbers of positive, negative, and complex zeros of f(x) = 3x4 - 5x3 - x2 - 8x + 4? @midhun.madhu1987 @kirbykirby

Answer 1

Positive: 2; negative: 2; complex: 4 or 2 or 0

Positive: 1; negative: 3 or 1; complex: 2 or 0

Positive: 3 or 1; negative: 1; complex: 2 or 0

Positive: 2 or 0; negative: 2 or 0; complex: 4 or 2 or 0

Answer 2

pLEASE HELP

Answer 3

@sky577 @tkhunny

Answer 4

\[\let\\\\f(x)=3x^4 - 5x^3 - x^2 - 8x + 4\]
look there are two sign changes one from 3x^4 to (-5x^3) and another (-8x) to 4
so there are 2 possible possitive zeroes

Answer 5

now try f(-x)

Answer 6

Alright

Answer 7

So, the answer will be the last choice or first

Answer 8

it will be
\[f(-x)= 3x^4 + 5x^3 - x^2 + 8x + 4 \]
here also two sign change one is 5x^3 to (-x^2) another is (-x^2) to 8x
so from here
two possible negative zeroes or two possible complex zeroes.

Answer 9

yeah it should be then the last one

Answer 10

Thanks so much

Answer 11

yw!!