Question

How many liters of fluorine gas can react with 32.0 grams of sodium metal at standard temperature and pressure? Show all of the work used to find your answer.

2Na + F2 yields 2NaF



Can anyone plz help me out with this?
@hartnn @Abhisar @Callisto @paki @Preetha

Answer 1

brb

Answer 2

okay @Abhisar

Answer 3

m back :D

Answer 4

ok..now temme the atomic mass of sodium

Answer 5

22.98977

Answer 6

yes..take it 23

Answer 7

okay :)

Answer 8

Now from the equation we can see that 2 moles of sodium needs 1 mole of fluorine gas. So 23*2=46 grams of sodium needs one mole of fluorine

Answer 9

So 32 grams will need 32/46 = 0.69 moles of fluorine

Answer 10

Now, one mole of any gas at STP has a volume of 22.4 litrres, so 0.69 moles of fluorine will have 0.69*22.4=15.58 L

Answer 11

and that will be our answer?

Answer 12

15.58 L

Answer 13

ok..lso y don't u try to put it urself on the basis of ur understanding and i'll correct u

Answer 14

ok

Answer 15

is it right?

Answer 16

@Abhisar

Answer 17

no of moles of fluorine that reacts with 32 gram of Na = 32/46=0.6956

1 mole of Fluorine at STP=22.4 L
So 0.69 moles of fluorine = 22.4*0.6956=15.58 L

Answer 18

Okay got it!! thanks sooo much for all your help your awesome!

Answer 19

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