Question

Given h(x)=x^2+5 find h^-1(x) (inverse!)

Could anyway please explain to me how to solve this problem step by step, I honestly have no idea how to do this. thanks:)

Answer 1

When you want to inverse something, that means you want to "swap" the domain with the range, therefore, the value of x would turn into y and y into x.

\[h(x)= x ^{2} + 5\] can be written as
\[y = x ^{2} + 5\]

then you swap the x with y, the new equation will be...

Answer 2

no idea

Answer 3

just change the letter x into y

Answer 4

and y into x

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we're trying to inverse it, it's sort or swapping it.

Example:
y +2 = x

and let say that y = 1 and x = 3, and you want to inverse it, that means you want to replace the value of x and y, into x=1 and y=3, therefore, what you did is

x + 2 = y
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do the same with the equation you've asked

Answer 5

i think i solved it, is the solution plus minus sqrt x-5