Use the following four coordinates to determine which one has a distance of 10 units from point C (1,2). (3,4) (7,10) (6,7) (8,9)
@math92130 @Mokeira @HDStorm @laurisve @amriju @juanpabloJR @j.youmans @Dr.Tehuti-mes @Pretty_in_pink @trexnapora someone please help
use the distance formula\[d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\]
Please elaborate what x1, x2..etc are for her help @sidsiddhartha
@sidsiddhartha do you mean this \[10=\sqrt{(1-x)^{2}+(2-y)^{2}}\] square both sides \[100=1+x ^{2}+4+y ^{2}\] \[x ^{2}+y ^{2}=95\]
yeah if there are two points in a plane with coordinates (x1,y1) and (x2,y2) then distence between them is \[d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\] now take \[x_1\rightarrow 1 ~~and ~~~y_1\rightarrow 2\] then it will be \[10=\sqrt{(1-x_2)^2+(2-y_2)^2}\] now squaring both sides \[100=(1-x_2)^2+(2-y_2)^2\]
I'm confused on what to do next
now check which pair satisfies this equation
This one! (7,10)
yup correct :)
Thank you can you help me with another one
yeah
Line AB has an equation of a line y=5x-2 and line DC has and equation of a line y=-5x-2. These two lines are parallel because the slope of the lines are the same perpendicular because the product of the slopes is -1 both representations of the same line neither parallel nor perpendicular
I know its not the 1st or 2nd
can u find the slopes of those lines
5x and -5x
they both have the same y intercept but I don't know how that answers the question
I think its the last one, but I'm not sure
sorryy connection got lost :(
yeah now try to compare with the standard equation \[y=mx+c\] comparing u'll get slope for the first line is m1=5 and for the second line m2=-5 so product of m1*m2=-25 which is not equal to -1 so they are not perpendicular and also \[m_1 \neq m_2\] they are also not parallel
exactly but I don't know wether its the last answer or second to last answer
although i'm pretty sure its the last one
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