MnO4- + S2O32- → Mn2+ + SO42-What is the oxidation half-reaction

Question

MnO4-  +  S2O32-     →     Mn2+   +   SO42-What is the oxidation half-reaction

jfraser · Answer

what's the definition of oxidation?

anonymous · Answer

S2O32 is a molecule?

jfraser · Answer

$S_2O_3^{-2}$ is an ion,

but what's the definition of oxidation?

anonymous · Answer

oxidation occur when oxidation number of a particle increase or specific particle lose electron.

anonymous · Answer

oxidation is the loss of ions
it is the gaining of oxygen atom 
or the loss of hydrogen ion

anonymous · Answer

in this reaction OH- contribute or H+?

anonymous · Answer

@moradi312 i thiNk OH-

jfraser · Answer

unless it's specifically told we always assume acidic. It doesn't matter for answering this question, because you have to identify what the oxidation state of each atom is, then see which one increases from reactant to products

anonymous · Answer

i want to balance this equation without balancing answer is:
$$S2O32-\rightarrow SO42-$$

anonymous · Answer

@moradi312 
i don't understand what you are saying

anonymous · Answer

oxidation half-reaction is:
S2O32−→SO42−

jfraser · Answer

if you want to balance that half-reaction, you can do it in either acidic or basic conditions. the rules and the steps are essentially the same

anonymous · Answer

i just want to be sure.

anonymous · Answer

ay, if anyone is studying biology i could sure use some help on my question

anonymous · Answer

$$5 H2O+ S2O32- \rightarrow 2 SO42- +10 H+ +8 e-  is balanced oxidation half-reaction$$

anonymous · Answer

am I right?

jfraser · Answer

looks right to me

midhun.madhu1987 · Answer

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