Question

Help please, chemistry
A laboratory experiment requires 4.8 L of a 2.5 M solution of sulfuric acid (H2SO4), but the only available H2SO4 is a 6.0 M stock solution. How could you prepare the solution needed for the lab experiment? Show all the work used to find your answer.
I did the first part
(4.8 L) x (2.5 M) / (6.0 M) = 2.0 L

Answer 1

Sorry that i deleted the other one i just wasn't specific

Answer 2

it's the same question. Solving for the volume needed to make the more dilute solution

Answer 3

http://openstudy.com/updates/53ecdab6e4b01789aba5212d

Answer 4

the 2L volume tells you that in order to make 4.8L of 2.5M solution, you need to take 2.0L of the concentrated 6M solution and dilute it with enough water to make the new total volume 4.8L

Answer 5

"Dilute it" that is what i don't understand how do i dot hat?

Answer 6

do that*

Answer 7

adding water to a concentrated sample "dilutes" it

Answer 8

2.0 L you mean

Answer 9

to any sample, but this example starts with 2.0L of concentrated acid and dilutes it with water until the total volume is 4.8L

Answer 10

For converting 2L of 6 M solution into 2.5M of 4.8 L solution you will have to add 2.8 L of water into it

Answer 11

Oh i get it I'm just trying to find how much i need to get to 4.8 that is why it is 2.8

Answer 12

yes. 4.8-2 = 2.8

Answer 13

Thanks i was confused

Answer 14

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