Question

The steps to derive the quadratic formula are shown below:

Step 1: ax2 + bx + c = 0
Step 2: x2 + b over ax + c over a = 0
Step 3: x2 + b over a x = - c over a
Step 4: x2 +b over a x + square of quantity of b over 2 times a = -c over a + square of quantity of b over 2 times a
Step 5: x plus b over 2 times a, all squared = -c over a + square of quantity of b over 2 times a
Step 6: x + b over 2 times a = square root of all of negative c over a plus the square of the quantity b over 2 times a
Step 7: x = - b over 2 times a ± square root of all of negative c over a plus the square of

Answer 1

Step 7: x = - b over 2 times a ± square root of all of negative c over a plus the square of the quantity b over 4 times a = -b over 2 times a ± square root of the quantity of b squared minus 4 times a times c over 4 times a squared= negative b plus or minus square root of b squared minus 4 times a times c over 2 times a

Which of the following statements best describes the first incorrect step?

In Step 4, square of quantity of b over 2 times a instead of b over 2 times a was added on both sides.

In Step 5, x plus b over 2 times a, all squared was written instead of x plus b over 4 times a, all squared .

In Step 6, -c over a was written instead of c over a inside the root.

In Step 7, b over 4 times a, all squared was written instead of square of quantity of b over 2 times a inside the root.

Answer 2

I believe step 4 and 5 are right but i dont know about 6 and 7

Answer 3

@Hero @SolomonZelman @Abhisar @Ail.A @JReed231 @Nurali @uri @kropot72 @kirbykirby @KlOwNlOvE @xapproachesinfinity @NoCopsForMiles

Answer 4

someone please i will give medal

Answer 5

@tejasvir @ganeshie8 @Gin_Ichimaru @geekfromthefutur @GoldenEagle @graffiboy1 @BassCatcher15 @Blink-182 @bibby @BVBLegacy @Brainybeauty @dan815 @dynasty<> @tejasvir @TheMilkyWay @miraclemilktea2 @math92130 @iceicebaby

Answer 6

sorry I cant give you the answer otherwise I will get banned and we don't want this to happen

Answer 7

can you help?

Answer 8

@graffiboy1

Answer 9

the quadratic formula is

Answer 10

\[x=\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\]

Answer 11

okay

Answer 12

\[ax ^{2}+bx+c=0\]

Answer 13

\[x=\frac{ -1 \pm \sqrt{1^{2}-4(1)(1)} }{ 2(1) }\]

Answer 14

\[x=\frac{ -1 \pm \sqrt{1-4} }{ 2 }\]

Answer 15

\[x=\frac{ -1 \pm \sqrt{-3} }{ 2 }\]

Answer 16

\[x=\frac{ \pm \sqrt{-4} }{ 2 }\]

Answer 17

\[x=\frac{ \pm 2 }{ 2 }\]

Answer 18

\[x=\pm1\]

Answer 19

are you sure bc you cant add -1 and \[\sqrt{-3}\]

Answer 20

@phi can you explain this?

Answer 21

owl-lover, your post is hard to read when typed out in words.

Answer 22

@owl-lover

Answer 23

oh sorry

Answer 24

is step 7 the answer? here:\[\frac{ -b }{ 2a }\pm \sqrt{\frac{ -c }{ a }+(\frac{ b }{ 4a })^2}=\frac{ -b }{ 2a }\]

Answer 25

but the last step might be the one with an error

Answer 26

nvm this is really hard thats not all of 7

Answer 27

can you screenshot the question

Answer 28

the (b/4a)^2 in step 7 should read (b/2a)^2

Answer 29

not sure how

Answer 30

and yes thats what i was thinking

Answer 31

http://www.wikihow.com/Take-a-Screenshot-in-Microsoft-Windows

Answer 32

its not working but i think i got it could you help with another