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Discrete Random variable question: http://i58.tinypic.com/23m7xw6.png I got 6.2 for E(R), but I can't seem to figure out how to get E(R^2)? anyone please! medals will be given :)D
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@ganeshie8
@kropot72 ?
\[\large E(R ^{2})=\sum_{}^{}r ^{2}p(r)\]
\[Var(R) = E(R ^{2}) - [E(R)]^{2}\]
thanks I figure it out!
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and Standard Deviation is the Square Root of Variance.
\[\large E(R ^{2})=1^{2}\times\frac{1}{5}+5^{2}\frac{2}{5}+10^{2}\frac{2}{5}\]
You're welcome :)
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