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Mathematics 18 Online
OpenStudy (anonymous):

Discrete Random variable question: http://i58.tinypic.com/23m7xw6.png I got 6.2 for E(R), but I can't seem to figure out how to get E(R^2)? anyone please! medals will be given :)D

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

@kropot72 ?

OpenStudy (kropot72):

\[\large E(R ^{2})=\sum_{}^{}r ^{2}p(r)\]

OpenStudy (midhun.madhu1987):

\[Var(R) = E(R ^{2}) - [E(R)]^{2}\]

OpenStudy (anonymous):

thanks I figure it out!

OpenStudy (midhun.madhu1987):

and Standard Deviation is the Square Root of Variance.

OpenStudy (kropot72):

\[\large E(R ^{2})=1^{2}\times\frac{1}{5}+5^{2}\frac{2}{5}+10^{2}\frac{2}{5}\]

OpenStudy (kropot72):

You're welcome :)

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