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Mathematics 19 Online
OpenStudy (anonymous):

Confused on Arctan and such: http://prntscr.com/4cu103

OpenStudy (anonymous):

Here's one way you can think about it. Let \(x=\tan^{-1}\left(\sin\dfrac{\pi}{2}\right)\). Then taking the tangent of both sides, you have \(\tan x=\sin\dfrac{\pi}{2}=1\). What value of \(x\) gives a tangent of 1?

OpenStudy (anonymous):

Tan is y/x on the unit circle, correct?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

One sec, my unit circle isn't loading :/

OpenStudy (anonymous):

π/4?

OpenStudy (anonymous):

yep that's right

OpenStudy (anonymous):

So is the answer π/4 or 1?

OpenStudy (anonymous):

nvm, now that I think about it, I understand. The answer is π/4

OpenStudy (anonymous):

You're solving for \(x\) in that equation I gave you. \[\tan x=1~~\iff~~\tan\frac{\pi}{4}=1~~\Rightarrow~~x=\frac{\pi}{4}\]

OpenStudy (anonymous):

Thanks, man/girl!

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