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Confused on Arctan and such: http://prntscr.com/4cu103
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Here's one way you can think about it. Let \(x=\tan^{-1}\left(\sin\dfrac{\pi}{2}\right)\). Then taking the tangent of both sides, you have \(\tan x=\sin\dfrac{\pi}{2}=1\). What value of \(x\) gives a tangent of 1?
Tan is y/x on the unit circle, correct?
Yes
One sec, my unit circle isn't loading :/
π/4?
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yep that's right
So is the answer π/4 or 1?
nvm, now that I think about it, I understand. The answer is π/4
You're solving for \(x\) in that equation I gave you. \[\tan x=1~~\iff~~\tan\frac{\pi}{4}=1~~\Rightarrow~~x=\frac{\pi}{4}\]
Thanks, man/girl!
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