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Mathematics 19 Online
OpenStudy (anonymous):

**FAN AND MEDAL**** What type of polynomial is x(x - 6)(x - 7)? and what is its degree?

OpenStudy (anonymous):

You need to expand it by multiplying.

OpenStudy (anonymous):

So (x^2-6x)(x-7) Then x^3-6x^2-7x^2+42 Now combine the like terms.

OpenStudy (anonymous):

ok, so i got 2x^2 - 13x^2 - 13

OpenStudy (anonymous):

you need to do them individually I think, so x(x-6) first. Then that times (x-7)

OpenStudy (anonymous):

thats not how you do this you do this: (x - 6)(x-7) then you get: 2x - 13x - 13, then you multiply that by x and get 2x^2 - 13x^2 -13

OpenStudy (anonymous):

Okay i screwed up lol.

OpenStudy (anonymous):

well if that's the answer, the degree is whatever the highest exponent is. So now you know that.

OpenStudy (anonymous):

so the degree is 2, so is it a trinomial?

OpenStudy (anonymous):

Well hang on, when you do the two binomials together you got 2x^2 - 13x - 13, right?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

Then you need to multiply them all by x if you haven't yet, so it'll be 2x^3 - 13x^2 - 13x.

OpenStudy (anonymous):

So it would be to the 3rd degree.

OpenStudy (anonymous):

READ WHERE I EXPLAINED HOW TO DO IT, IT HAS ALREADY BEEN MULTIPLYED BY X

OpenStudy (anonymous):

thats not how you do this you do this: (x - 6)(x-7) then you get: 2x - 13x - 13, then you multiply that by x and get 2x^2 - 13x^2 -13. That's what you wrote, but when you do the first ones x times x, that should be x^2.

OpenStudy (anonymous):

so it would be 2x^2 - 13x - 13 times x.

OpenStudy (anonymous):

a trinomial is a polynomial with 3 terms, so does - 13 count as a term.....Where did the extra x come from?

OpenStudy (anonymous):

- 13 does count, and I'm not too sure what you mean by the extra x...

OpenStudy (anonymous):

were you trying to say i forgot the x that oes on the -13? because i just noticed that

OpenStudy (anonymous):

And i say extra x because I already multiplyed the whole equation by x and then you multiplyed it by x a SECOND time which is why i ask where you got the second x

OpenStudy (anonymous):

Well sort of... What I'm saying is that when you were multiplying the first two binomials, (x - 6)(x - 7) it should have equaled x^2-7x-6x+42.

OpenStudy (anonymous):

which is x^2-13x+42.

OpenStudy (anonymous):

and that's before you multiplied it by x, so it should be x(x^2-13x+42)

OpenStudy (anonymous):

that doesnt change that its a second degree trinomial

OpenStudy (anonymous):

Yes it does, It would make it to the third degree.

OpenStudy (anonymous):

because (x)(x^2) = x^3

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

So is that it?

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