Question

Finding Zeros: http://prntscr.com/4cuhv3
I understand that -2i has a conjugate (+2i) but I'm not to sure how to find the other zeros (if there are any)

Answer 1

@SithsAndGiggles

Answer 2

well you can solve this problem by plugging in the differnt values and see which fit or you can proceed a sfollows

Answer 3

multiply (x-2i)(x+2i) to get a quadratic that divides evenly into your quartic.
then find the roots of the quotient (a quadratic)

Answer 4

Well, you know the factored form is: \[
(x-2i)(x+2i) (\ldots)
\]So multiply them first.

Answer 5

Then you can divide the resulting polynomial out through synthetic division.

Answer 6

you can proceed as phi as suggested

Answer 7

or notice we can factor your quartic (almost like a quadratic)
into
(x^2 + 4) ( x^2 -36)

Answer 8

alright, thanks! I will work it out in a minute and see what I get

Answer 9

that last suggestion by phi is the easiest way

Answer 10

either x^2 + 4 = 0

giving x^2 = -4 - this gives rise to the roots 2i and -2i

or x^2 - 36 = 0

giving ?