Question

Find the vertices and foci of the hyperbola with equation ((x+4)^2/9)-((y-5)^2/16)=1

Answer 1

\[\frac{ (x+4)^2 }{ 9 }-\frac{ (y-5)^2 }{ 16 }=1\]

Answer 2

lmfao

Answer 3

a^2 = 16, then a = ?
answere=(8, -4) and (-2, -4)

Answer 4

a=4

Answer 5

Choices

Vertices: (5, 0), (5, -8); Foci: (5, -8), (5, 0)

Vertices: (5, -1), (5, -7); Foci: (5, -9), (5, 1)

Vertices: (-1, 5), (-7, 5); Foci: (-9, 5), (1, 5)

Vertices: (0, 5), (-8, 5); Foci: (-8, 5), (0, 5)

Answer 6

b=3

Answer 7

Vertices: (5, 0), (5, -8); Foci: (5, -8), (5, 0)