solve by substitution method
0.05x-0.01y=2.6
0.26x+0.18y=22.8
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OpenStudy (triciaal):
usually easier to work with whole numbers so start by getting rid of the fraction
multiply by 100
OpenStudy (anonymous):
5x-y=26
26x+18y=228
OpenStudy (triciaal):
to solve by substitution express one variable in terms of the other then use in the second equation.
you will have one equation with one variable.
solve for this variable.
use this value in the original to find the value of the other variable.
OpenStudy (anonymous):
i dont understand how to do that
OpenStudy (triciaal):
using the first equation
5x - y = 260
y = 5x -260
using this in the second equation
26 x + 18 (5x - 260) = 2280
can you continue
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OpenStudy (anonymous):
116x-4680=2280
OpenStudy (triciaal):
keep going
OpenStudy (anonymous):
x=60
OpenStudy (triciaal):
you have x now find y
OpenStudy (anonymous):
by pluggin in 60 to 5x-y=260?
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OpenStudy (triciaal):
yes
OpenStudy (anonymous):
y=-40
OpenStudy (triciaal):
watch your sign
OpenStudy (anonymous):
its a negative isnt it?
OpenStudy (triciaal):
y = 5x -260
= 5*60 -260 =300- 260 = 40
y = 40
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OpenStudy (anonymous):
5x60+y=260
300+y=260 subtract -300
y=-40
OpenStudy (triciaal):
5x-y = 260
OpenStudy (anonymous):
which is correct
OpenStudy (triciaal):
look at the original
OpenStudy (anonymous):
ok so we have to swtich it and it is a postive
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OpenStudy (anonymous):
the correct answer is 40
OpenStudy (triciaal):
x = 60 and y = 40
always good practice to check your solution in the original
OpenStudy (anonymous):
ok thanks
OpenStudy (triciaal):
plug these values in the second equation to check
OpenStudy (triciaal):
here is a review of the steps
1. pick a variable and find the expression for that variable using one of the equations
2. use this expression in the other equation.
3. solve for only variable in this equation
4. use this value to find the value of the other variable.
5. check your solution in either of the original equation
any questions?