Question

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Answer 1

B and C parts are right but whats closure property?

Answer 2

x^2>0
23>0
so x^2 + 23 > 0

Answer 3

closure property
to show that its always positive

Answer 4

A:
You said you had

\[hypotenuse^2 = (x-7)^2 + (2x -10)^2\]
I think this is right...can't we just take the square root of everything?
\[\sqrt{hypotenuse^2} = \sqrt{(x-7)^2} + \sqrt{(2x -10)^2}\]
\[hypotenuse=(x-7)+(2x-10)\]
\[hypotenuse=3x-17\]

Answer 5

oh ok that makes sence, so what about C?

Answer 6

area was found by multiplying two polynomials
and the answer is a polynomial too

Answer 7

thanks alot :)

Answer 8

that is wrong
hypotenuse2−−−−−−−−−−√=(x−7)2−−−−−−−√+(2x−10)2−−−−−−−−√
can't be
hypotenuse=(x−7)+(2x−10)

Answer 9

@NinjaDevo are you sure you worked that hypotenuse correctly?

Answer 10

so is that wrong?

Answer 11

of course

Answer 12

ok, now im more confused than when i started

Answer 13

Sorry for the confusion....I thought you could do that.
These guys seem like they would be able to help you out better than I can.

Answer 14

hypo^2 = (x-7)^2 + (2x-10)^2
hypo^2 = 5x^2 - 54x + 144

Answer 15

oh, so did you distribute to get that?

Answer 16

yep

Answer 17

ok, that makes sence. thank you very much

Answer 18

it's just a use of phythagarus theorem