Question

Find x3 - 2y2 - 3x3 + z4 if x = 3, y = 5, and z = -3.

Answer 1

im not good in math

Answer 2

Ok so we start Off by substituting
z for -3
y for 5
x for 3
\[\Large x^3 - 2y^2 - 3x^3 + z^4\]
\[\Large (3)^3 - 2(5)^2 - 3(3)^3 + (-3)^4\]
So acording to pemdas we do exponents first
\[\Large 3*3*3=27\]
\[\Large 5^2 = 25\]
\[\Large 3*3*3 = 27\]
\[\Large -3*-3*-3*-3 = -81\]
\[\Large 27 - 2(25) - 3(27) + -81\]
Since The Next thing to do on pemdas is multiply we multiply
\[\Large 2*25=50\]
\[\Large 3*27=81\]
\[\Large 27-50-81 - 81\]
So can you solve that?

Answer 3

So based on this the answer is -23

Answer 4

and i meant +81 :/

Answer 5

wait so its -23?

Answer 6

Yes it is -23. Everything that Cameron did is correct.

Answer 7

ok thanks cause I got -185